No convex polygon with 7 or more sides can tessellate.
false
Each interior angle of a regular heptagon measures 900/7 degrees.The interior angles of all polygons meeting at a point must sum to 360 degrees. But that would require 360 / (900/7) = 2.8 - that is you would require 2.8 regular heptagons to meet at each vertex. Since it is not possible to have a fraction of a heptagon. the tessellation required by the question is impossible.
No. Because tessellation is about using lost (infinitely many) copies of a polygon to cover a surface, One polygon does not comprise a tessellation.
A regular polygon has 3 to 5 or more sides and angles, they should be all equaled. A regular tessellation means a tessellation made up of congruent regular polygons.
No, it cannot. I was doing my own tessellation project when I came across this question. In order for a polygon to tessellate, the sum of the angles surrounding one point must be 360 degrees (think of it this way, if you spin in a circle, you spin 360 degrees.) So, if a heptagon has a total angle measure of 900, each andgle is approx. 128.57 degrees. 128.57 cannot fit evenly into 360. Hence, a heptagon whose total angle measure is 900 cannot be used by itself to tessellate.
true
Tessellations are named based on the number of polygons located at a vertex. For example: A regular tessellation, made from only triangles is named 3.3.3
Yes it is a tessellation.
Strictly speaking, no, because a semi-regular tessellation must be based on regular polygons and rhombi are not regular polygons. However, octagons and rhombi can be used to make a non-regular tessellation.
Non-visible tessellation or non-existent tessellation, perhaps.
How to Make a Tessellation?
A regular tessellation or semi-regular tessellation or none.