Q: Can a remainder be greater than nine?

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The remainder CAN'T be greater than the divisor, not if you do the division correctly.

If the remainder were greater than the divisor, you'd be able to take another divisor out of it.

No.

less than

The remainder is less than the divisor because if the remainder was greater than the divisor, you have the wrong quotient. In other words, you should increase your quotient until your remainder is less than your divisor!

Absolutely not possible

Greater than

Remainder can't be greater than or equal to 8.

0.0261

The remainder must always be smaller.

Nine tenths is greater than one third.

grater

127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.

Because if the remainder was larger than the divisor, then the divisor could go into the dividend again.

9. The divisor must be greater than the remainder. A 1 digit divisor that is greater than 8 can only be 9.

If the remainder is greater than the divisor then you can divide it once more and get one more whole number and then have less remainders.

No.

Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.

104.

No. If your remainder is greater than your divisor that means you haven't finished dividing as much as you can yet. For example, if you divide 100 by 10 and get 9 with a remainder of 10, that means that you can still divide once more to find the final answer of 10.

Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.

It is any number greater than 0 that is divisible by 2 without remainder. There are infinitely many of them.

Yes, because that is how remainder is defined. If the remainder was bigger, you would subtract one (or more) modular values until the remainder became smaller than the modulus.

The problem would not end

the quotient would be wrong