No, in the sense that the units of the length of the base and the units of the area are different; one is measured in meters, the other, meters squared (or ft. and sqft., etc.). However, they can have the same numerical part. So a triangle could have a base of 1 meter and end up having an area of 1 meter squared. This would be the case with a triangle of base 1 meter and height 2 meters: A = (bh)/2 = (1 m * 2 m)/2 m2= 1 m2.
Similarly, a circle can have the same numerical part for its circumference as for its area. This is the case for a circle of radius 2 meters: C = 2πr = 2π(2 m) = 4π m; A = πr2 = π(4 m)2 = 4π m2. Remember that though the numerical part is the same, 4π, the dimensional part, the units (m and m2), is different.
Yes, a parallelogram and a triangle can have the same base and area. If a triangle and a parallelogram share the same base and height, the area of the triangle will be half that of the parallelogram. However, if the triangle is formed by using one of the sides of the parallelogram as its base and the height is the same, they can have the same area. Thus, they can have the same base but will only have equal areas under specific conditions.
The parallelogram has twice the area of the triangle if their bases are the same and their heights are the same. Area triangle = 1/2 base x height. Area parallelogram = base x height.
I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.
A triangle and a parallelogram can have the same area if the base and height of the triangle are proportional to the base and height of the parallelogram. Specifically, the area of a triangle is given by ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ), while the area of a parallelogram is ( \text{Area} = \text{base} \times \text{height} ). Therefore, if the base of the parallelogram is twice the base of the triangle and they share the same height, their areas will be equal.
A triangle twice as high as a parallelogram with the same base has the same area.
The area of a parallelogram is base x height and the area of a triangle is 1/2 x base x height. So the area of a parallelogram will always be 2 times bigger than a triangle with the same base and height.
two right triangles = full rectangle That is - if you multiply height times base of a triangle, the area will be 1/2 of a rectangle having the same height, and a width the same as the triangle base.
no
The exact same as the original triangle.
twice the area of the triangle with the same base an height.
Only if the two triangles have the same base and height then they have the same area, because an area of a triangle OS the base times the height divided by two.
It is base x height for the parallelogram. That is twice the area of a triangle which is: 1/2 base x height. (Base and height being the same for both cases).