If a point is on the perpendicular bisector of a segment, then it is equidistant, or the same distance, from the endpoints of the segment.
In general, they are not. In an isosceles triangle, the perpendicular bisector of the base is the same as the bisector of the angle opposite the base. But the other two perp bisectors are not the same as the angle bisectors. Only in an equilateral triangle is each perp bisector the same as the angle bisector of the angle opposite.
The median is a line from a vertex to the midpoint of the opposite line and an altitude is a line from a vertex to the opposite line which is perpendicular to the line. These are NOT the same thing in most triangles. The only time they could be the same is in an equilateral triangle.
Two lines cannot be parallel and perpendicular at the same time.
the middle point * * * * * In 2 dimensions: also any point on line forming the perpendicular bisector of the line segment. In 3 dimensions: the plane formed by the perpendicular bisector being rotated along the axis of the line segment. In higher dimensions: Hyperplanes being rotated along the same axis.
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
Yes. The orthocenter is the intersection of the altitudes; the circumcenter is the intersection of the perpendicular bisectors of the three sides of the triangle. The perpendicular bisector of and altitude to a given side are parallel, so they can coincide at the common center only if they are the same; that means that the opposite vertex is on the perpendicular bisector, so the other two sides are equal. Thus each pair of sides are equal, so the triangle is equilateral.
It will if isosceles or equilateral. The first will have a single line: the bases' perpendicular bisector produced through the apex. The second will have 3 in the same way.
Drawing perpendicular bisector for a line:Place the sharp end of a pair of compasses at one end of the line, and open it to just over half of the line. Draw an arc which must intersect the line in the position described. Then put the sharp end at the other of the line and, keeping the compassing at the same length, draw another arc which intersects the first one twice and also the line. Then draw a straight line through the two places where the arcs intersect. This line is the perpendicular bisector. Drawing perpendicular bisector of angle:Places the sharp end of the compass at the point of the angle and, after having opened it arbitraily wide, draw an arc which intersects the two lines meeting to form the angle each once in the said position. Then remove the compass and, always keeping it opened at the SAME length, place the sharp end at each of the two places where the previous arc cuts each of the two lines meeting to form the angle. In this position with the described length, draw a small arc at each of the said places, which should cross each other. Draw a straight line from the point of the angle to this crossing. This should be the bisector of the angle.
No, it's not true.
-- Draw a line segment from one point to the other.-- Construct the perpendicular bisector of the line segment..-- Every point on the perpendicular bisector of the line segmentis equidistant from the two original points.==========================================================================Whereupon the first contributor observed:Yes, that works, no matter how you set the compass, as long as it's more than 1/2 the distancebetween the two points. Every setting of the compass will give you a pair of points that areequal distances from the original two. As you find more and more of them ... with differentsettings of the compass ... you'll see that all the equal-distance points you're finding all lieon the same straight line. That line is the perpendicular bisector of the line between the twooriginal points, just as we described up above.
the circumcenter, orthocenter, and centriod, when connected together i Euler's line. the angle bisector of the non base angle is the same thing.