no because then it would be undefined
It is a top-heavy, or improper fraction but only if the denominator is positive.It is not defined if the denominator is 0 and the numerator is any positive integer.It need not be an improper fraction if the denominator is negative and the numerator is positive - and therefore greater - but of a smaller magnitude.For example, consider 2/(-3): the numerator = 2 is bigger than denominator = -3, but the fraction is not improper.
An improper fraction has a numerator greater than the denominator. When the numerator and denominator are equal, that's called "1."
3 as an improper fraction with a denominator of 5 = 15/5
7/10 is not an improper fraction as the numerator is smaller than the denominator. An improper fraction is a fraction where the numerator is larger than the denominator, such as 10/7.
If the fraction's numerator is greater than its denominator, then it already is an improper fraction. If its numerator is smaller than its denominator, then there's nothing you can do to it to turn it into an improper fraction.
It is an improper fraction when the numerator is greater than the denominator
The improper fraction with a denominator of 6 that is equivalent to 5.5 is 33/6
That's an improper fraction.
An improper fraction
An improper fraction has a numerator equal to or greater than its denominator.
An improper fraction has a numerator greater than the denominator. When the numerator and denominator are equal, that's called "1."
An improper fraction is one in which the numerator is larger than the denominator.