Since we're talking about complex numbers, let's divide 82 by (1+i) or (82)/(1+i). Get rid of (1+i) on the bottom by mutiplying by the conjugate (1-i). We have (82)(1-i)/(1+i)(1-i) or (82-82i)/2 which is 41-41i. :)
1,2,6,12,41,82 all go into 82.
Yes, 2 x 41 = 82All these go into 82 evenly: 1, 2, 41, 82.
No. 82 is not evenly divisible by 61.
1, 2, 41, 82.
7 ÷ 82 = 7/82 ≈ 0.0854.
No.
Each of these numbers goes evenly into 82: 1, 2, 41, 82.
Any of its factors which are: 1, 2, 41 and 82
Exactly 82 times
623 ÷ 82 = 7 remainder 29
They are its factors which are: 1, 2, 41 and 82
No.