2 and 41
41x2=82
Suppose one of the numbers is x. Then, because they sum to 82, the other number is 82 - x. Then their difference gives the equation x - (82 - x) = 24 or 2x - 82 = 24
1, 2, 41, 82
164
Any of its factors which are: 1, 2, 41 and 82
They are its factors which are: 1, 2, 41 and 82
2 and 41
1, 2, 4, 41, 82, and 164
Since we're talking about complex numbers, let's divide 82 by (1+i) or (82)/(1+i). Get rid of (1+i) on the bottom by mutiplying by the conjugate (1-i). We have (82)(1-i)/(1+i)(1-i) or (82-82i)/2 which is 41-41i. :)
The list of numbers that are divisible by 82 is infinite. The first four are: 82, 164, 246, 328 . . .
41x2=82
82 = 2 x 41
1, 2, 41, 82.
The prime numbers between 82 and 108 are 103 and 107.
0.82 and 41/50 are equivalent to 82%
They are: 79+3 = 82