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Yes and also 0.5 times the product of its diagonals
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What is the area of the rhombus?
The area of a rhombus is calculated by multiplying the base x the vertical height.
What is the base of a rhombus whose area is 7886.2 sq cm and height is 95.7 cm?
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
How is the area of a rhombus derived?
Base multiplied by its perpendicular height and measured in square units.
What is the missing diagonal of a rhombus if the area is 120ft2 and the other diagonal is 16 feet?
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
How do you find the base of a trapazoid when you have the height and area?
Area = Base * Height so Base = Area/Height
What is the area of the rhombus?
The area of a rhombus is calculated by multiplying the base x the vertical height.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm?
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
What is thr area of the rhombus shown below AC 17 BD15 AB11.2?
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
What is the base of a rhombus whose area is 7886.2 sq cm and height is 95.7 cm?
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
How is the area of a rhombus derived?
Base multiplied by its perpendicular height and measured in square units.
What is the area and perimeter of a rhombus?
Area equals base times height. The perimeter is 4 times the length of one side.
What is the area to a rhombus with the base equals 7ft height equals 3ft?
A=BxH =7x3 =21ft squared
What is the missing diagonal of a rhombus if the area is 120ft2 and the other diagonal is 16 feet?
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
What is the maximum area for a rhombus with sides 25 cm?
Its area is base times perpendicular height or 0.5 times the product of its diagonals
How do you find the base of a trapazoid when you have the height and area?
Area = Base * Height so Base = Area/Height
How do you solve measurements in a rhombus?
A rhombus is a quadrilateral where all sides have the same length. Rhombuses have some special properties that help you determine their measurements. Sides: if you know the length of one side, you know the length of the rest of the sides. Angles: the angles which are adjacent to each other in a rhombus are supplements to each other. So if you have a rhombus with angles A, B, C and D, then A + B = 180 degrees, and A + D = 180 degrees. This also means that B = D. And because the sum of the angles of any quadilateral is 360 degrees, A = C. Area: The area of a rhombus is the base * height, where the base is an arbitrary side of the rhombus and the height is the distance between the base and the opposite side of the rhombus. If you draw a perpendicular line between the base and the opposite side, the length of that line will be the height.
Where did the area of a rhombus come from?
If you multiply the lengths of the two diagonals, and divide by 2, you get the area of a rhombus. How does this work: Call the diagonals A & B for clarity. Diagonal A will split the rhombus into 2 congruent triangles. Looking at one of these triangles, its base is the diagonal A, and its height is 1/2 of diagonal B. So the area of one of the triangles is (1/2)*base*height = (1/2)*A*(B/2) = A*B/4. The other triangle has the same area, so the two areas together make up the whole rhombus = 2*(A*B/4) = A*B/2.
