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No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component.

Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.

Q: Can the magnitude of a vector be lesser than its component?

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no a vector cannot have a component greater than the magnitude of vector

No.

No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component

yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....

No, by definiton, a unit vector is a vector with a magnitude equal to unity.

Related questions

no a vector cannot have a component greater than the magnitude of vector

can a vector have a component greater than the vector magnitude

No.

No.

No.

No. The magnitude of a vector can't be less than any component.

No.

No.

No.

No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component

No.

No. The magnitude of a vector can't be less than any component.