no a vector cannot have a component greater than the magnitude of vector
No.
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
No, by definiton, a unit vector is a vector with a magnitude equal to unity.
yeah, it can. for example consider two antiparallel vectors of magnitude 5,3 whose resultant is 2, which is smaller than both components.....
no a vector cannot have a component greater than the magnitude of vector
A vector component can never be greater than the vector's magnitude. The magnitude of a vector is the length of the vector and is always greater than or equal to any of its individual components.
No, a vector's component cannot be greater than the vector's magnitude. The magnitude represents the maximum possible magnitude of a component in any direction.
No, a vector component is a projection of the vector onto a specific direction. It cannot have a magnitude greater than the magnitude of the vector itself.
No, a component of a vector cannot be greater than the magnitude of the vector itself. The magnitude of a vector is the maximum possible value that can be obtained from its components.
No.
No.
No.
No.
No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.
No, a vector cannot have zero magnitude if one of its components is not zero. The magnitude of a vector is determined by the combination of all its components, so if any component is not zero, the vector will have a non-zero magnitude.
No, a vector can not have any components greater than itself.