no.
You need to know the speed at which it was fired, which you haven't revealed. When you have that, here's the procedure: -- Calculate the horizontal and vertical components of the "launch" speed. Hint: At 45°, they're both 0.7071 of the launch speed. Set the horizontal speed aside for later. -- Take the vertical component of the speed, and calculate how long it would take a stone, tossed upward at that speed, to hit the ground. The answer is some number of seconds. -- Now go back to the horizontal component of speed. Calculate how far a car or a stone can go at that speed, in the amount of time it took the other stone to hit the ground. This whole method makes two important assumptions: 1). No air resistance. The air has no effect on the behavior of the projectile. 2). The ground is flat, and so is the Earth, at least for the distances that this shot will involve. At your level in Physics, you would have no chance of solving it without these assumptions.
The horizontal acceleration i.e. Vx throughout the trajectory remains constant only of the air resistance is neglected. The gravity can affect the y-component of velocity but is unable to affect its x-component. Acceleration (delta V) does not occur unless a change comes into play per Newton. Gravity does not effect x but air resistance would. Likewise, projectiles launched from e.g. an explosion experience a reducing delta V in that acceleration from an explosion is subject to the inverse square rule.
Vertical lines have no effect whatsoever on the garments, but when the lightingis just right, they do help the wearer convey the appearance of being taller andless corpulent.
No inductor is perfect and has a capacitive and resistive component. As frequency increases, these components have more effect on the circuit operation. A capacitive component would be out of phase and be the imaginary value.
horizontal projectile means to project horizontaly from any height h and it forms equation of parabola if we throw any object it goes horizontal and after this it goes down and by the equation s=ut+1/2at*twe can find following things from it # time ofprojectile # distance travelled #effect of gravity
Horizontal and vertical components which need to be treated independently from each other when working out either the horizontal or vertical motion.
Unbalanced force of gravity will not have any effect on horizontal component but makes a variation in the vertical component
No, horizontal velocity and vertical velocity are independent and have no effect on each other.
In the absence of air resistance, the force of gravity has no effect on the horizontal component of a projectile's velocity, and causes the vertical component of its velocity to increase by 9.8 meters (32.2 feet) per second downward for every second of its flight.
In the absence of air resistance, the force of gravity has no effect on the horizontal component of a projectile's velocity, and causes the vertical component of its velocity to increase by 9.8 meters (32.2 feet) per second downward for every second of its flight.
No. That's why the whole idea of orthogonal (perpendicular) components is so useful. They have no effect on each other, so you can investigate and solve them separately.
-- Gravity causes the vertical component of projectile motion to vary according to the local acceleration of gravity. -- Gravity has no effect at all on the horizontal component of projectile motion.
The force of gravity points towards the center of the earth ... the direction we call "down". The force has no horizontal component, so it can't have any effect on horizontal speed.
One reason is that anything which happens in one of the orthogonal directions has no effect on what happens in another orthogonal direction. Thus, for example, the horizontal component of a force will not have any effect in the vertical direction.
virtical direct effect is an action against the state by individuals while horizontal direct effect is against another individual or company
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.