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How do you calculate the distance of a projectile fired at a 45 degree angle?
Wiki User
∙ 12y ago
You need to know the speed at which it was fired, which you haven't revealed.
When you have that, here's the procedure:
-- Calculate the horizontal and vertical components of the "launch" speed.
Hint: At 45°, they're both 0.7071 of the launch speed.
Set the horizontal speed aside for later.
-- Take the vertical component of the speed, and calculate how long it would take
a stone, tossed upward at that speed, to hit the ground. The answer is some
number of seconds.
-- Now go back to the horizontal component of speed. Calculate how far a car
or a stone can go at that speed, in the amount of time it took the other stone
to hit the ground.
This whole method makes two important assumptions:
1). No air resistance. The air has no effect on the behavior of the projectile.
2). The ground is flat, and so is the Earth, at least for the distances that
this shot will involve.
At your level in Physics, you would have no chance of solving it without
these assumptions.
Wiki User
∙ 12y ago
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What is the largest angle a projectile can be launched?
180 Degree
How does angle affect the distance of a projectile?
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
At what launch angle or angles will the projectile land at half of its maximum possible range?
The half maximum range of a projectile is launched at an angle of 15 degree
What is the formula for a 30 degree angle?
That depends what you want to calculate.
Why the projectiles thrown with angle 30 degree and 90 degree have the same range?
No. The range of the projectile thrown at 90 degrees is 0. It goes straight up and then straight down!
What angle above the horizontal should a projectile be fired to produce the greatest downrange distance?
its 45 degree
What is the largest angle a projectile can be launched?
180 Degree
How does angle affect the distance of a projectile?
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
How do you set up a catapult to get the maximum distance possible using one elastic bungee cord?
Release the projectile at a 45 degree angle.
Does a projectile's distance covered decrease when fired at an angle above forty-five degrees?
The optimal angle to fire a projectile if the objective is distance is 45 degrees. It follows that the distance traveled decreases whether the angle is increased or decreased from 45.
At what launch angle or angles will the projectile land at half of its maximum possible range?
The half maximum range of a projectile is launched at an angle of 15 degree
Why does a catapult shoot best from a 45 degree angle?
The [horizontal] range of a projectile is maximised when it shoots at a 45 degree angle. This is true if air resistance is ignored so that the only force acting on the projectile is gravity.
What angle a projectile thrown to achieve maximum vertically distance traveled?
90
What is maximum rang of projectile motion?
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
What is the factor influence the distance and time in projectile motion?
projection speed projection angle projection height
What is the formula for a 30 degree angle?
That depends what you want to calculate.
If you keep the velocity of projection constant and change the angle of projection from 75 to 45 what will happen to the horizontal distance the projectile travels?
The horizontal distance will be doubled.
