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The set of the first numbers of the ordered pairs in a relation?
Usually the set of x values.
How can you tell from looking at two ordered pairs that the line containing them has a slope of zero?
The y-values for the two ordered pairs would have to be the same (for example, (3,1) and (6,1) would be such a set of ordered pairs). Because the slope of a line is (y1-y2)/(x1-x2), for the slope to be zero, y1=y2.
How do you write ordered pairs from a function table?
The function table will have two columns, one for the x-value and one for the y-value. Form ordered pairs (x,y) by inserting the values from one row of the table.
What are the ordered pairs for 20?
The Ordered Pairs are 1x20, 2x10, and 5x4.
When putting together a table of x and y values to form ordered pairs what is the first step of the process?
establish variables to plug in for the values of X and Y
What is difference between Ordered pairs and different ordered pairs?
There's only one thing that's different: the spaces. If you count spaces, it's most likely your answer is wrong.
Are these ordered pairs in direct variation?
It is not possible to answer the question with no information about which ordered pairs!
What is -1 in ordered pairs?
-1 is a one-dimensional entity. It can have no equivalent in ordered pairs.
How do you graph function g?
use y = g(x) make a table of y values for several x values Find max/min values using derivative. graph the ordered pairs.
How are ordered pairs and ratios similar?
You can write ordered pairs as ratios to determine if two sets of ordered pairs form a linear or non-linear relationship. In a table of x,y values, the ordered pairs are listed as the x value first, then the corresponding y value. Remove from the table and write as a ratio of x over y, (or y over x, if you like). In a linear relationship, all the ratios of x over y, (or y over x) are equivalent.
How do you find y in a set of ordered pairs?
Y is the second number in a set of ordered pairs.
What are the relationship between pairs of data values could be examined from a?
someone answer this
