Yes.
If you graph distance vs. time, the slope of the line will be the average speed.
Its initial speed cannot be 20 m, as stated in the question. Secondly, if the initial speed is correctly given, then there is no need to calculate it!
You can use a graph to calculate speed.
You can calculate speed by taking the gradient (dy/dx) from a Distance-time graph since s=d/t
speed is the gradient under the distance vs time graph which is change in distance /change in time
Speed (in the radial direction) = slope of the graph.
If you graph distance vs. time, the slope of the line will be the average speed.
Its initial speed cannot be 20 m, as stated in the question. Secondly, if the initial speed is correctly given, then there is no need to calculate it!
You can use a graph to calculate speed.
You can calculate speed by taking the gradient (dy/dx) from a Distance-time graph since s=d/t
If you only have the speed/time graph, you can't calculate force out of it. You could if you also knew the mass of the object that's speeding along, but not with the speed alone.
That's not correct. If you have a graph of distance as a function of time, the speed is the slope of the graph.
speed is the gradient under the distance vs time graph which is change in distance /change in time
distance divided by speed is equal to timetraveled.
If you know the initial speed (u), acceleration (a) and time (t), then the final speed, v = u + at.
True
We suspect that you're also given a line on the graph. If so, then the initial speed is the slope of the line at the initial position. To get the real slope of the line, you need to know the scales of the axes. If the scales aren't the same, then the real slope of the line isn't what it looks like, and has to be calculated by measuring its progress along both axes just after the initial position.