No, that is simplified as much as possible.
how do you find the solution to x<3
Replace a value for x, then solve for y, to find the corresponding value for y. Repeat for other values of x.
Because this question has more than one variable( x and y) the solution is impossible to find (a number). To make it easier to find x or y, x = a - y + 3 y = 3 - x - a where a = y - x + 3
6*x + 30 + 4*x = x+3; the solution is x = -3
There is one solution. x = -3
I can't integrate a-x /x-3 ?
The equation ( x - 3 = 0 ) can be solved by isolating ( x ). By adding 3 to both sides of the equation, we find that ( x = 3 ). Thus, the solution to the equation is ( x = 3 ).
The equation that has the solution x = -3, is, precisely:x = -3 If you want anything more fancy, you can add some number (the same number to both sides), multiply by some number (the same number to both sides), etc.
No, it is not a solution.
The equation that has a solution of ( x = -3 ) can be written as ( x + 3 = 0 ). When you solve this equation, you subtract 3 from both sides, leading to ( x = -3 ). Alternatively, any equation that can be manipulated to reach this solution, such as ( 2x + 6 = 0 ), will also have ( x = -3 ) as a solution.
There can be no solution to an algebra equation because of limitations of the domain. For example,x+3 = 2 has no solution if the domain for x is the set of positive integers,x*3 = 2 has no solution if the domain for x is the set of whole numbers,x^3 = 2 has no solution if the domain for x is the set of rational numbers,x^2 = -2 has no solution if the domain for x is the set of real numbers.Alternatively, the equation has no solution if it can be reduced to a false statement. For example,x + 2 = x + 3 can be simplified to 2 = 3 which is false and so there is no solution.
4/3 x radius3 x pi = volume 4/3 x 43 x pi = 268.09