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Q: Can you find two consecutive odd integers whose sum is 116?

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They are: 57+59 = 116

The numbers are 57 and 59.

The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.

The sum of two consecutive integers will always be an odd number.

These are really simple to solve. Just divide by 3 and that gives you your middle integer. In this case 348/3 = 116 so the trio are 115, 116 and 117.

The two odd integers are 57 and 59.

57+59 = 116

The numbers are 57 and 59.

The numbers are 116, 118 and 120.

The GCF of any consecutive non-zero integers is 1.

There is no possible solution. Suppose the three numbers are n, n+2 and n+4 where n is odd Then you require 3n + 6 = 116 ie 3n = 110 But 110 is not a multiple of 3, hence there is no solution to the question.

116 + 118 = 234. Answer is 118. Took 5 seconds to do.

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123

If both 116 and 412 are included, then 264.

114 115 116 117 118 119 120 121 122 123 124 125 126

It is 180 -64 = 116 and 64 plus 116 = a supplementary angle of 180 degrees

116

115 + 116 = 131

the square root of 116

The numbers are 29, 30, & 31. 29 * 4 = 116 ....... 31 * 3 = 93; 93 + 23 = 116

Two nearest integers are 116 and 118

114, 115 & 116

The LCM is: 116

116 and 219 are integers, not fractions.

Algebraically.X + ( X + 2) = - 1162X + 2 = - 1162X = - 118X = - 59X + 2 = - 57- 59 (+) - 57 = - 116( - 57, - 59 )------------------solution set