The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.
The LCM is: 116
Well, darling, if you want to get technical, the two numbers that multiply together to equal 116 are 4 and 29. But really, who cares about numbers when you could be out there living your best life instead of doing math?
Double of 58 is 116.
All multiples of 116 are divisible by 116. There is an infinite number of multiples of 116.
They are: 57+59 = 116
The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.
The numbers are 57 and 59.
The sum of two consecutive integers will always be an odd number.
These are really simple to solve. Just divide by 3 and that gives you your middle integer. In this case 348/3 = 116 so the trio are 115, 116 and 117.
The two odd integers are 57 and 59.
57+59 = 116
The numbers are 57 and 59.
The GCF of any consecutive non-zero integers is 1.
The numbers are 116, 118 and 120.
There is no possible solution. Suppose the three numbers are n, n+2 and n+4 where n is odd Then you require 3n + 6 = 116 ie 3n = 110 But 110 is not a multiple of 3, hence there is no solution to the question.
116 + 118 = 234. Answer is 118. Took 5 seconds to do.