Q: What are consecutive integers with the sum of 116?

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The consecutive integers whose sum is 51 are 16, 17, and 18.

No two consecutive integers have a sum of 2012.

It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.

No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.

The sum of any two consecutive integers must be an odd number. So this question is incorrect.

Related questions

They are: 57+59 = 116

The two odd integers are 57 and 59.

57 and 59

The numbers are 57 and 59.

The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.

There is no set of three consecutive integers whose sum is 71.

There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

116 + 118 = 234. Answer is 118. Took 5 seconds to do.

Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.

The numbers are 55, and 57. Two consecutive integers have an odd sum.

The consecutive integers whose sum is 51 are 16, 17, and 18.