If these lengths did form a right triangle then Pythagorean theorem would be satisfied
a^2+b^2 = c^2
since 10 is the largest number it must be the hypotenuse (c)
left side=9^2+3.6^2, right side= 10^2
LS= 93.96, RS= 100, LS does NOT equal RS
Therefore these three lengths cannot combine to form a triangle.
No.
316 = (3 x 100) + (1 x 10) + (6 x 1)
A triangle has 3 sides.
Yes, they are a simple multiple of the Pythagorean Triple 5-12-13
A triangular number or triangle number counts the objects that can form an equilateral triangle. 10 objects can be formed into an equilateral triangle.
No.
316 in expanded form is 300 + 10 + 6.
Yes the given dimensions would form a right angle triangle.
If you mean units of 6 8 and 10 then yes they can form the sides of a right angle triangle.
The given dimensions would not form a right angle triangle but in general the are of a triangle is 0.5*base*perpendicular height
316 = (3 x 100) + (1 x 10) + (6 x 1)
it is an acute triangle.
Expanded form means to separate each number out to its place in a place value chart or table. So with 12, the 1 is in the _____ place and the 2 is in the _____ place. So with 12, it's really 10 + 2.With 316, the 3 is in the ______ place, the 1 is in the _____ place, and the 6 is in the _____ place. So 316 would be _____ + ______ + ______.
No. For example, say the two angles are 10° and 20°. Then the other angle is 180°-10°-20°=150° and that is not a right angle. But if the triangle has two equal acute angles of 45 degrees then the 3rd angle must be 90 degrees which will form a right angle triangle.
10^2 + 12^2 is not equal to 16^2, so it is not a right triangle.
The hypotenuse of a right triangle with legs of 8 and 10 is: 12.81
A triangle has 3 sides.