The 1st is a right angle triangle and the 2nd is a scalene triangle.
Yes
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
the average of 8 10 12 14 16 is 12
There is no such right triangle. You have defined the relationship between three sides of a triangle that does not have a 90 degree angle. In a right triangle the sum of the squares of the shorter sides equals the square of the longest side and 12 + 22 = 5 ; 42 = 16 it does not equal 5 The angles in a triangle with sides 1, 2, 4 units can be found by applying the cosine rule.
The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
Yes
The dimensions given do not support Pythagoras' theorem for a right triangular prism which will have a right angle triangle at each end
Yes, because the equation for solving a right triangle's hypotenuse is a2 + b2 = c2. So lets say 16 is a and 12 is b and 20 is c. Now a=256 and b=144 and c=400. Because 256 + 144 = 400 these measurments would make a right triangle. Understand?
yes
What is 12 in ? And what is 16 in ? ? Are they the lengths of two sides of the triangle ? Are they the length of one side and the height of the triangle ? The area of any triangle is 1/2 of the product of (length of its base) x (its height).
Using Pythagoras' theorem its hypotenuse will be 20
Lets work it out:- If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
If you mean sides of 10, 12 and 16 then yes a triangle be constructed because the sum of its 2 smaller sides is greater than its longest side.
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
No. 42 + 72 = 16 + 49 = 65 whereas 102 = 100 Since these two are unequal, by Pythagoras' Theorem, the triangle cannot be right angled.
The other leg length is 16.