10^2 + 12^2 is not equal to 16^2, so it is not a right triangle.
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The 1st is a right angle triangle and the 2nd is a scalene triangle.
Yes
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
There is no such right triangle. You have defined the relationship between three sides of a triangle that does not have a 90 degree angle. In a right triangle the sum of the squares of the shorter sides equals the square of the longest side and 12 + 22 = 5 ; 42 = 16 it does not equal 5 The angles in a triangle with sides 1, 2, 4 units can be found by applying the cosine rule.
To test use PYTHAGORAS ; h^2 = a^2 + b^2 34' is the longest side (h) , hence 34^(2) = 1156 a & b are 16 & 30 Hence 16^() + 30^(2) = 256 + 900 = 1156 , which equatres with 34^(2) . Thereby satisfies the Pythagorean Equation. Hence it is a Right angled triangle. So the sides 16,30, & 34 form a right triangle.