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Q: Can you make 24 using only numbers 6 6 9 13 only once?

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3! = 6.

4*3*2 = 24 of them.

only using the numbers once

2,5,13,647,809

8

If you want 4-digit numbers, there are 24 of them.

None.

998,000

1+2+3+4+5+6+7+8+9 = 45

8 plus 1 , minus 5, plus 7 + 13

There is only one combination. In a combination the order of the numbers does not matter so the only combination is 0123456789. This is the same as 1326458097

(7 + 5 - 9) x 8 = 24

how do i make 17 using only 2 4 6 8

-9

I may be wrong but it seems impossible. There probably is proof somewhere if it is.

24 of them.

(5+7)*(5-3)=12*2=24

Yes we can make it.

if your using whole numbers, u can only use 3

1

36 - 18

There is no such set of numbers.

75 - 32

No. Not if the numbers are to be used only once. There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required. If the numbers can be used more than once then 2*2*5*5 is one possible solution.

Not possible