depens if the number can be used in any order
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
Besides no repeats, we also assume that the first digit can't be zero.The first digit can be any digit except zero ... 9 choices. For each of those . . .The second can be any one of 9 digits ... zero, and the 8 that were not the first one. For each of those . . .The third can be any one of the 8 remaining digits. For each of those . . .The fourth can be any one of the 7 remaining digits. For each of those . . .The fifth can be any one of the 6 remaining digits. For each of those . . .the Sixth can be any one of the 5 remaining digits.The total number of possibilities is: (9 x 9 x 8 x 7 x 6 x 5) = 136,080 .If there were no restrictions, then 6 digits could make 1,000,000 different numbers.The restrictions have eliminated 86.4 percent of them.
24
There is no way to write any one or more of those six digits in such a way as to equal 47.
500
Six, if you don't repeat any digits.
The first can be any one of 10 digits. For each of those . . .The second can be any one of the nine digits not the same as the first. For each of those . . .The third can be any one of the nine digits not the same as the second. For each of those . . .The fourth can be any one of the nine digits not the same as the third. For each of those . . .The fifth can be any one of the nine digits not the same as the fourth. For each of those . . .The sixth can be any one of the nine digits not the same as the fifth. For each of those . . .The seventh can be any one of the nine digits not the same as the sixth. For each of those . . .The eighth can be any one of the nine digits not the same as the seventh. For each of those . . .The ninth can be any one of the nine digits not the same as the eighth.The total number of possibilities is: (10 x 9 x 9 x 9 x 9 x 9 x 9 x 9 x 9) = 430,467,210 .If matching adjacent digits were allowed there would be 1,000,000,000 possibilities.So the restriction has eliminated 56.95% of them.
they are 24 you can make with the numbers 1-4 or any other 4 digits here they are123412431432142313421324213421432431241323412314312431423421341232413214423142134312432141324123* * * * *WRONG!These are permutations, not combinations. In a combination theorder of the digits does not matter so there is only one combination of 4 digits out of 4.
Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.
4 x 3 x 2 ie 24
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
I do not believe there are any two digits that can make 302.