they are 24 you can make with the numbers 1-4 or any other 4 digits here they are
1234
1243
1432
1423
1342
1324
2134
2143
2431
2413
2341
2314
3124
3142
3421
3412
3241
3214
4231
4213
4312
4321
4132
4123
* * * * *
WRONG!These are permutations, not combinations. In a combination theorder of the digits does not matter so there is only one combination of 4 digits out of 4.14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
There are 15380937 of them.
300
9
There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
There are 13,244 of them.
There are 15380937 of them.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
900000
300
To calculate the number of 3-number combinations from the numbers 1-20, we can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 and r = 3. Plugging these values into the formula, we get 20C3 = 20! / 3!(20-3)! = 1140. Therefore, there are 1140 possible 3-number combinations from the numbers 1-20.
9