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It t is an odd multiple of 5, you can express it as 5(2n+1), where "n" is some integer. The square of that expression is 25(2n+1)2 = 25(4n2+4n+1) = 100n2+100n+25. Since the first two terms are multiples of 100 (remember, "n" is an integer), you have some multiple of 100, plus 25 - in other words, a number that ends with 25.

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11y ago

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