The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
2n can be split into 2 n's so: n+n then add one to one of the n's and subtract one from one of the n's n+1+n-1 ^two consecutive odd integers^
Write x and y in terms of integers, which we call a and b. For some integer, x = 2a + 1 y = 2b + 1 Multiplying them, you get: xy = (2a+1)(2b+1) = 4ab + 2a + 2b + 1 Since the first terms are even, adding one makes the final result odd.
Odd. Even + Even = Even Odd + Odd = Even Odd + Even = Even + Odd = Odd
49 is an odd number numbers ending in 1,3,5,7,9 are odd.
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
Looking at the graph of the function can give you a good idea. However, to actually prove that it is even or odd may be more complicated. Using the definition of "even" and "odd", for an even function, you have to prove that f(x) = f(-x) for all values of "x"; and for an odd function, you have to prove that f(x) = -f(-x) for all values of "x".
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
A will always be an odd number.
The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as: Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So, S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900
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No, not necessarily. 121 is a palindrome number with 3 digits (odd) and is divisible by 11. So this satisfies the premise, but 101, 111, 131, etc are not divisible by 11.An example which satisfies the premise does not prove it true, but one which contradicts the premise is enough to prove it false.
9
Find their GCF.
3x3=a That's just one example, though. You could switch it up saying: 3xa=9 or vice versa. It's kind of hard to depict it with algebra, but I think what I said before is pretty much what you would do.You can't prove it. Example: 3*9=27 You should try to prove something that is valid.
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Use variables, such as "m" and "n", for integers. In that case, your even number might be "2m", and your odd number might be "2n + 1". See what happens when you subtract one from the other.