A scalene acute triangle is a triangle with all sides of different lengths and all angles less than 90 degrees. It does not have any equal sides or equal angles. Therefore, a picture of a scalene acute triangle would show three lines of different lengths connecting to form a triangle with three angles less than 90 degrees.
Cannot show a picture, but visualise a right angled triangle. Then imagine one of the [acute] vertices chopped off by a line parallel to the opposite side. You will then have a trapezium with two right angles. Very crudely, it should look like the figure below: ---\ |__\
Using a protractor which should give a measure of a 90 degree angle and two acute angles that add up to 90 degrees.
No.Finding an obtuse triangle that does not have a greater area than any acute triangle will show the statement is false:Consider the obtuse triangle with sides 25, 25, 40 cm; andthe acute triangles with sides 2, 2, 2 cm and 40, 40, 40 cmArea of (A) obtuse triangle = 40 x 12 ÷ 2 = 240 cm2Area of (B) acute 2, 2, 2 cm triangle = 2 x √3 ÷ 2 = √3 cm2 ~= 1.7 cm2Area of (C) acute 40, 40, 40 cm triangle = 40 x (20 x √3) ÷ 2 = 400 x √3 cm2 ~= 692.8 cm2So you can clearly see that area of acute triangle (C) is greater than that of obtuse triangle (B) which is greater than acute triangle (A).Thus the area of obtuse triangle (B) is not greater than that of any acute triangle.(Obtuse triangle A has angles approx 37o, 37o, 106o, whereas triangles B and C are equilateral acute triangles with angles 60o, 60o, 60o.)
show the drawing
An acute angle is a angle less than 90 degrees
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No. All equilateral and equiangular triangles are acute. (All angles are equal to 60°, which is less than a right angle [90°]); however, the converse (which is what was asked) is not true.A triangle can have all three angles be less than 90°, but not be an equilateral triangle.An example is a triangle with angles of 80°, 60°, and 40°. It is scalene and acute.From the Law of Sines: a/sin(A) = b/sin(B) = c/sin(C), you can show that sin(80°) does not equal sin(60°) or sin(40°), so none of sides a, b, and c, are equal.You could have an acute isosceles triangle like: 80°, 80° and 20° angles, as another example. From the Law of Sines, you can show that two of the sides are equal, but the third side (opposite the 20° angle) is not equal to either of the other 2.
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Since a right triangle has 180 degree angles in it, you know 2 angles already. One is the 90 degree angle, since the triangle is a right one. The other is 40 degrees, as in your statement. 90 plus 40 is 130. 50 degrees is the missing angle since 50 + 40+ 90 equal 180 degrees. Hopefully that helped you.
A Scalene Triangle is a triangle where all three sides are different in length.
I need angles both sides of a picture, where I can fix a picture of princess Karen H. Chaer