No To find out if a regular polygon tessellates you have to do A=180(sides-2) all over 2. Then you do 360/answer and if it is a whole number it does tessellate. * * * * * Correct answer but the reasoning is limited to regular polygons. According to that logic, a pentagon should not tessellate. But there are 15 pentagons (all irregular) which will.
Some can, but not all. For example, rhombi, rhomboids, oblongs, and isosceles triangles can tessellate; however, most irregular polygons cannot. * * * * * True, but an incomplete answer. All triangles and quadrilaterals, whether regular or irregular, will tessellate. No regular pentagon will tessellate but (as of 2016), there are 15 irregular pentagons which will tessellate. There are 3 convex hexagons, (regular and 2 irregular) which will tessellate. No polygon with 7 or more sides, even if it is regular, will tessellate.
It has 3 sides It has 3 interior angles that add up to 180 degrees Its 2 base angles are equal It has 2 equal sides It will tessellate It has a perimeter which is the sum of its 3 sides It has an area which is 0.5*base*perpendicular height
A parallelogram has 2 pairs of opposite parallel sides It has 4 interior angles that add up to 360 degrees It has 2 diagonals Its perimeter is the sum of its 4 sides It will tessellate Its area is base times perpendicular height
No, because if you use the formula to find an angle measure: 180(n-2)/n (this formula only works for regular shapes) where n is the number of sides, then the measure of one of the angles equals 135. Then in order to tessellate 135 must be a multiple of 360. But 135 x 2 = 270, and 135 x 3 = 405, so a regular octagon does not tessellate.
It is a 4 sided quadrilateral It has 4 interior angles that add up to 360 degrees It has 2 diagonals It has 2 pairs of opposite parallel sides It will tessellate
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It is a 4 sided quadrilateral Its opposite sides are parallel Its 4 interior angles add up to 360 degrees It has 2 diagonals It will tessellate
Both have 4 sides Both have 2 diagonals Both have 4 equal right angles Both will tessellate Both are in the same class as quadrilaterals
Both have 4 sides Both have 2 diagonals Both have 4 equal right angles Both will tessellate Both are in the same class as quadrilaterals
If you subtract two from the amount of sides there are in the polygon than mutiply that by 180 you than divide that number by the original amount of sides there was by 360 and if it goes into it without a decimal it tessalates. Ex. (10-2)180/360
It is a 4 sided quadrilateral It has 4 interior angles that add up to 360 degrees Its opposite angles are equal It has 2 pairs of opposite parallel sides It has 2 diagonals It will tessellate Its perimeter is the sum of its 4 sides Its area is base times perpendicular height