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Lets call the number of chickens x, the number of ducks y, and the number of turkeys z.

First equation: You need to buy 100 birds

x+y+z = 100 [1]

Second equation: You need to spend $100

0.50x + 3.00y+10z = $100 [2]

Use simultaneous equations to solve: Multiply the first equation by 10 so you can cancel out the z's.

10x+10y+10z=1000 [1]

- 0.5x+3y+10z=100 [2]

9.5x +7y=900 (3)

9.5x=900-7y

x = (900-7y)/9.5

7y = 900-9.5x

y = (900-9.5x)/7

Now to find z

Multiply the first equation by 3 and subtract [2] from [1] to rid of the y.

3x+3y+3z=300

- 0.5x+3y+10z=100

2.5x - 7z = 200

2.5x = 7z + 200

x = (7z+200)/2.5

7z = 2.5x-200

z = (2.5x-200)/7

So now we have all values of x, y, and z.

y = (900-9.5x)/7

z = (2.5x-200)/7 Both y and z are now written in terms of x.

Recall that x+y+z = 100

Substitute the values in for y and z

x+(900-9.5x)/7+(2.5x-200)/7 = 100 x + 900/7 - 9.5x/7 + 2.5x/7 - 200/7 = 100 Collect the like terms x+1+x = 100

2x + 1 = 100

2x = 99

x = 49.5

y= (900-9.5x)/7

x = 49.5)=> y = (900-49.5)/7

y = 61.4

z = (2.5x-200)/7

z = -10.9 well...the addition of the three is 100, and the cost of them would be $99.95.. but how do you have -11 turkeys? I think you might need another equation(?).

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Q: Chickens are 0.50 and ducks are 3.00 and turkeys are 10.00. You need to spend 100.00 and buy 100 birds?
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