1/(4+i5) = (4-i5)/(16+25)
= (4/41)-i(5/41)
The standard from for a complex number is a + bi, where a and b can have any real value including zero and i = √-1
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Not necessarily.
-4=4ei*pi
Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.
Yes, a+bi is standard form for a complex number. The numbers (a) and (b) are both real and i is √(-1)
The standard form of a complex number is a+bi. So the standard form of the negative square root of 5i is 0-√(5i).
That already is in standard form.
28.6 is the standard notation. The standard form(also called scientific notation) is: 2.86 × 101
It isn't clear in what form you have the complex number. But you can change it from the form (absolute value, angle) to the form (real part + imaginary part) using the polar-rectangular conversion available on scientific calculators (and the other way round, with the rectangular-polar conversion). Note that a complex number in the form (real part + imaginary part) is most appropriate for addition and subtraction, while a complex number of the form (absolute value, angle) is most appropriate for multiplication or division, so depending on the operations, you may want to convert back and forth several times.
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A COMPLEX NUMBER CAN BE CONVERTED INTO A POLAR FORM LET US TAKE COMPLEX NUMBER BE Z=a+ib a is the real number and b is the imaginary number THEN MOD OF Z IS SQUARE ROOT OF a2+b2 MOD OF Z CAN ALSO BE REPRESENTED BY r . THEN THE MOD AMPLITUDE FORM IS r(cos@Very interesting, but -i is not a complex no. it is a simple (imaginary) no. with no real part.