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Yes in equilateral triangle.

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Q: Could the median of a triangle be the perpendicular bisector?
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Whats a segment that is equally distant from two endpoints of the segment of a triangle?

The description seems a bit confusing (to me) but it sounds like it could be a perpendicular bisector of a side of a triangle.


Is median and the altitude of a triangle the same?

The median is a line from a vertex to the midpoint of the opposite line and an altitude is a line from a vertex to the opposite line which is perpendicular to the line. These are NOT the same thing in most triangles. The only time they could be the same is in an equilateral triangle.


How would the construction be different if you changed the compass setting in step 4 of the perpendicular bisector construction?

If the compass angle is changed, the entire geometric shape being drawn is different. For example, if a triangle is being drawn, it could change from an obtuse triangle from a ninety degree triangle.


In the diagram below xy is the perpendicular bisector of jk?

It could be, but without the diagram it is not possible to be certain.


How do you find center of a circle given 3 points on the circle?

You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.


How do you bisect an obtuse angle?

In the same way that you bisect an acute triangle. Alternatively, you could extend one of the rays of the obtuse angle so that you have an acute angle. Bisect that angle and then draw a perpendicular to the bisector of the acute angle through the vertex.


What is the approximate length of the base of an isosceles triangle if the congruent sides are 3 feet and the vertex angle is 35 degress?

The median of an isosceles triangle from its apex is also the perpendicular bisector of the base. This line divides the triangle into two congruent right angled triangles whose hypotenuse is 3 feet and whose apical angle is 35/2 = 17.5 degrees. If the base of the original triangle was 2b cm then sin(17.5) = b/3 so that b = 3*sin(17.5) = 0.9cm so that the base was 2b = 1.8 feet Alternatively, you could use the sine rule on the triangle:


Is a right triangle a perpendicular shape?

Not necessarily. It is a plane shape which could be horizontal.


Which shape could never have perpendicular lines a circle a triangle a rectangle or a square?

A circle !!!!!!


Which shape has no parallel sides but at least 1 pair of adjacent perpendicular sides?

It could be a right angle triangle


Name all types of triangles for which the point of concurrency is inside the triangle?

The answer depends on what point of concurrency you are referring to. There are four segments you could be talking about in triangles. They intersect in different places in different triangles. Medians--segments from a vertex to the midpoint of the opposite side. In acute, right and obtuse triangles, the point of concurrency of the medians (centroid) is inside the triangle. Altitudes--perpendicular segments from a vertex to a line containing the opposite side. In an acute triangle, the point of concurrency of the altitudes (orthocenter) is inside the triangle, in a right triangle it is on the triangle and in an obtuse triangle it is outside the triangle. Perpendicular bisectors of sides--segments perpendicular to each side of the triangle that bisect each side. In an acute triangle, the point of concurrency of the perpendicular bisectors (circumcenter) is inside the triangle, in a right triangle it is on the triangle and in an obtuse triangle it is outside the triangle. Angle bisectors--segments from a vertex to the opposite side that bisect the angles at the vertices. In acute, right and obtuse triangles, the point of concurrency of the angle bisectors (incenter) is inside the triangle.


Is a quadrilateral perpendicular?

It could be but does not have to be... (Perpendicular to what?)