Interior angles of any polygon: (N-2)*180 = sum of interior angles when N is the number of sides
It can be but it also could be an irregular polygon
If an interior angle is 3580o there is a slight problem: a full turn is 360o and 3580o is more than a full turn.If the sum of the interior angles is 3580o, there would benumber_of_sides = 3580o ÷ 180 + 2= 218/9Another slight problem as the number of sides must be an integer.Thus I am lead to assume the question is:How many sides does a regular polygon have if one interior angle is 358o?But an interior angle of a regular polygon can't be greater than 180o. Another problem.ONE interior angle could be 358o, but then there could be three more angles of 1o, 0.5o and 0.5o; or four more angles of 1o, 1o, 1o, 179o; or five more angles, etc.Only solution possible is that there is no such (regular) polygon, or it is a polygon with an indeterminate number of sides (if one interior angle is 358o).
It depends. It could be anything.
You could measure it using a protractor, derive it from basic geometric properties (for example angles of a regular polygon), or calculate it using trigonometry.
It could be an irregular polygon with different sides or a regular polygon with equal sdes
It could have any amount of sides...angle doesn't matter.
It could be any size at all, just as long as all 29 of them add up to 4,860 degrees.If the polygon is regular, then each interior angle is 16717/29 degrees.
It could be three. It could be a triangle with angles of 174, 3 and 3 degrees. If it is a REGULAR polygon, though, there is a more specific answer. Interior angle = 174 deg implies exterior angle = 6 deg. Sum of ext angles = 360 deg so there must be 360/6 = 60 sides to the polygon.
It could be an obtuse triangle. If it were a regular polygon then each of its external angles would be 180 -140 = 40 degrees. The sum of the external angles of any polygon is 360 degrees. So if each is 40 degrees, there must be 360/40 = 9 of them. So the polygon is a nonagon, BUT ONLY IF IT IS A REGULAR POLYGON.
It can be but it also could be an irregular polygon
If an interior angle is 3580o there is a slight problem: a full turn is 360o and 3580o is more than a full turn.If the sum of the interior angles is 3580o, there would benumber_of_sides = 3580o ÷ 180 + 2= 218/9Another slight problem as the number of sides must be an integer.Thus I am lead to assume the question is:How many sides does a regular polygon have if one interior angle is 358o?But an interior angle of a regular polygon can't be greater than 180o. Another problem.ONE interior angle could be 358o, but then there could be three more angles of 1o, 0.5o and 0.5o; or four more angles of 1o, 1o, 1o, 179o; or five more angles, etc.Only solution possible is that there is no such (regular) polygon, or it is a polygon with an indeterminate number of sides (if one interior angle is 358o).
360 degrees, it could be a square or a rectangle
It depends. It could be anything.
Yes, it is
You could measure it using a protractor, derive it from basic geometric properties (for example angles of a regular polygon), or calculate it using trigonometry.
It could be an isosceles right triangle, or it could be a non-regular specimen of any polygon with more than three sides.
It could be any, as polygon is a general term for a shape with many sides, so, a regular hexagon and a regular octagon are both polygons.