radius=12.4+/-0.5mm length=243.3+/-0.5mm 1)length+width (12.4+/-0.5mm)+(243.3+/-0.5mm) (12.4+243.3)+/-(0.5+0.5) 255.7+/-o.1 2)length-width (243.3-12.4)+/-(0.5+0.5)mm 230.9+/-0.1
Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
the volume of a steel sheet plate is < length *breath *height >
Outer volume = pi*142*40 cm3 Inner volume = pi*122*40 cm3 Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3 = pi*52*40 = 6535 cm3 approx.
Length X Width X Depth = volume
Volume in cubic units = pi*radius2*length
This depends on what type of steel. The density of carbon steel (one of the most common types of steel) is 7.85g/cm3Density = m/vradius of rod = 3.25mm (radius is 1/2 of diameter)3.25mm = .325 cm1 meter = 100cmvolume of cylinder = (pi)(radius)^2(h) = 33.18Density * Volume = mass7.85 * 33.18 = 260.46260.46 grams
young modulus remain unaffected ...as it depends on change in length ..
The density of steel is around 490 pounds per cubic foot, depending on grade. I'm assuming the steel bar is a cylinder because you gave me a diameter. If it is not, I am completely wrong. The volume of a cylinder is pi times the radius squared times height. Pi is about 3.14159. The radius squared is 0.01085069444 feet. The height is 20 feet. The volume of the steel bar must be 0.68176866291519189 cubic feet. Therefore the bar must weigh about 334 pounds. Hmm, seems too heavy..
Use the formula for a cylinder to find out the volume. Then multiply the volume by the density of steel (about 7900 kg/m3 - but it may vary slightly depending on the type of steel).
The question cannot be answered sensibly. The weight of an object depends on its volume and volume depends on the length, breadth and height of the object. Given only the length it is impossible to give an answer. It would, for example, be impossible to distinguish between 12 inches of a steel wire and 12 inches of a steel block!
Need more information, but here are some examples for pipe elbows; you need to enter the elbows' centerline radius: 10" steel pipe with a 2R or 10" radius: if it is a 90 degree ell C/L-to-END is 10"; for a 76 degree ell it is 7.81" 10" steel pipe with a 3R or 15" radius: if it is a 90 degree ell C/L-to-ENC is 15"; for a 76 degree ell it is 11.72" The way to calculate this is to draw a right triangle with the smaller angle being 38 degrees (half of the 76 degree angle). The length of the triangle's "side adjacent" to the angle will be the length of the ell's centerline radius (15" in the case of the above 3R elbow). Multiply the tangent of the angle of 38 degrees by the length of the ell's centerline radius to get the length of the ell's "centerpoint-to-end" length.
volume of steel multiplied by7850= wt of steel in kgs. Please note that wt of 1 Cum steel is 7850 kg Volume of steel bar can be calculated = cross-sectional area of bar X length cross-sectional area of Bar= pie x d X d/4 (where d is diameter of bar)