Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
If the Smaller inner radius is r, Larger inner radius is R, and the Length of the pipe is L then Vol = 1/3*pi*L*(R2 + Rr + r2)
Take the inside diameter, from inner edge to opposite inner edge and going through the middle. Divide this by two to give you an inside radius. Multiply this by itself to give the radius squared, then multiply this by Pi to give inside area. Finally, multiply this by the length of the pipe to give the volume.
Measure the length of the pipe and the inner Dia of the pipe. 2 x pi x Radius x length is the inner surface area
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
If the Smaller inner radius is r, Larger inner radius is R, and the Length of the pipe is L then Vol = 1/3*pi*L*(R2 + Rr + r2)
Take the inside diameter, from inner edge to opposite inner edge and going through the middle. Divide this by two to give you an inside radius. Multiply this by itself to give the radius squared, then multiply this by Pi to give inside area. Finally, multiply this by the length of the pipe to give the volume.
let the outer radius of the ring be R inner radius r n cross sectional radius be y then the volume of the ring will be (pi)y2 X (pi)(R-r)/2 i.i the cross sectional area multiplied by the length of the ring when it was a line the length is taken at the midpoint of the thickness of the ring = (R-r)/2
Outer volume = pi*142*40 cm3 Inner volume = pi*122*40 cm3 Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3 = pi*52*40 = 6535 cm3 approx.
Measure the length of the pipe and the inner Dia of the pipe. 2 x pi x Radius x length is the inner surface area
The area volume of a given container is limited by the inner dimensions- found by multiplying the length times the width times the heighth, notated as LxWxH. The weight capacity is another consideration.
The area volume of a given container is limited by the inner dimensions- found by multiplying the length times the width times the heighth, notated as LxWxH. The weight capacity is another consideration.
A hollow metal cylinder has inner radius a, outer radius b, length L, and inside the metal as a function of the radius r from the cylinder's axis.
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
You must use the relationship between the inner radius and the outer radius. The relationship could very well be different every time you run into a problem like this, and I can't answer the question this time because you haven't described any relationship between them.
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
With the information given in the question you cannot. The volume of the pipe is pi(R2 - r2)*L where R = outer radius = outer diameter*0.5 = ID/2 + thickness = 108 mm r = inner radius = inner diameter*0.5 = ID/2 = 100 mm L = length = 1000 mm Next, to convert volume to mass, you need to multiply by the density. You then need to multiply the mass by the gravitational acceleration to convert to weight. If the mass is in kilograms, and the gravitational acceleration is in metres/second2 the result will be in Newtons, the SI unit for weight.