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it is shaped roughly like a bell... a bell curve.

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14y ago
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Q: Deviation IQ scores produce a normal curve that is shaped roughly like?
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The distribution of ACT scores in recent years has been roughly normal with mean 20.9 and standard deviation 4.4 The quartiles of any distribution are the values with cumulative proportions 0.25 and?

17.7 and 20.9


What percent of the scores in a normal distribution will fall within one standard deviation?

It is 68.3%


If the standard deviation of 10 scores is 0?

If the standard deviation of 10 scores is zero, then all scores are the same.


How many of scores will be within 1 standard deviation of the population mean?

Assuming a normal distribution 68 % of the data samples will be with 1 standard deviation of the mean.


If standard deviation of 10 scores is 0?

All the scores are equal


The standard deviation is the square root of the average squared deviation of scores from the?

mean


What is the difference between z-score and t-score?

T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.


What role do z-scores play in the transformation of data from multiple distributions to the standard normal distribution?

None.z-scores are linear transformations that are used to convert an "ordinary" Normal variable - with mean, m, and standard deviation, s, to a normal variable with mean = 0 and st dev = 1 : the Standard Normal distribution.


Is the different between an individual score and mean of the group of scores is called deviation?

No, it is called the absolute deviation.


How do you find the semi-interquartile range with only the mean and standard deviation?

In general, you cannot. If the distribution can be assumed to be Gaussian [Normal] then you could use z-scores.


How much is 84 percentile equals mean plus 1 standard deviation or mean plus 1.4 standard deviation. Can you give me reference also please?

The cumulative probability up to the mean plus 1 standard deviation for a Normal distribution - not any distribution - is 84%. The reference is any table (or on-line version) of z-scores for the standard normal distribution.


What is the mean absolute deviation of the bowling scores?

This question cannot be answered unless the bowling scores are provided.