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y = 3√x
y = 3x^(1/2)
y' = 3(1/2)x^(1/2 -1)
y'= (3/2)x^(-1/2)
y' = 3/[2x^(1/2)]
y' = 3/(2√x)
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∙ 15y ago
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Square yards in 22 feet by 24 feet?
22 x 24 = 528 sq ft. 1 sq yard = 9 sq ft (3 x 3). So 528 sq ft = 58.67 sq yards
5 ft46 ft what is the square yards?
1 yard = 3 feet 1 sq yard = 3 x 3 = 9 sq feet 5 x 46 = 230 sq ft = 230 ÷ 9 = 25.56 sq yd (2dp)
What is 18 x 24 in square feet?
Assuming 18 inch x 24 inch, result = (18/12) x (24/12) sq feet = 1.5 x 2 = 3 sq feet
How many acres is 170 feet by 70 feet?
1 acre is 4840 sq yards. Now 1 sq yard = 9 sq feet (3 feet x 3 feet), so 1 acre = 43560 sq feet. your area is 170 x 70 sq feet = 11900 sq feet. So this is 11900/43560 of an acre, answer = 0.273 acre.
Simplify the radical square root of 108?
√108 = √(36 x 3) = √36 x √3 = 6√3
What is the factored form of the square root of 75?
sq. root of 75 = sq. root of (25 x 3) = (sq. root of 25)(sq. root of 3) = 5(sq. root of 3)
How do you simplify 3 root 7 squared?
(3 root 7) squared = (3 root 7) (3 root 7) = (3x 3) ( sq root 7 x 7) = 9 x sq root 49 = 9 x 7 = 63
The x intercepts of y equals x2-2?
4
F -1 x - square root of x?
f(x)=x2f -1(x)=sq. root(x)__________________y2=x [invert y](y2)-1=x = 1/y2=xsq. root(1/y2)= sq. root (x) [y can't be squared, root both sides](1/y)=sq. root(x)y-1=sq. root(x)
What is the square root of 12 in simplest form?
square root of 12 = sq rt of (4 x3) = 2 x sq rt 3
Don't get why Tangent 60 degrees equals 50 x sq root of 3 should be sq rt of 3 divided by 50?
Because: tan(60) = square root of 3
Square root of 1296?
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36
Square root of 484?
Find the factors of 484484= (4)(121)Square root of (484) = Sq. root (4 x 121) = Sq. root (4) x sq. root of (121) = 2(11) = 22
X2 plus 5x plus 7 equals 0 what is the solution?
x2 + 5x + 7 = 0; a = 1, b = 5, c = 7; D = b2 - 4ac = 52 - 4(1)(7) = 25 - 28 = -3 x = (-b +&- sq. root of D)/2a x = (-5 +&- sq. root of -3)/2 x = [-5 +&- (sq. root of 3)i]/2
2x3 - 2x2 - x plus 1?
2x3 - 2x2 - x + 1 = 2x2(x -1) - (x - 1) = (x - 1)(2x2 -1) = (x - 1){[(sq. root of 2)(x)]2 -12} = (x - 1)[(sq. root of 2)(x) - 1][(sq. root of 2)(x) + 1]
What is the solution set for x2-4x equals 8?
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
2X Times Square root of X?
I think it's x^(3/2) x*x=x^2 sq.rt. x * sq. rt. x= x so x* sq. rt. x should be x^(1.5)...i think cuz each sq. rt. is worth half an exponent of 1. x^(1/2) = sq. rt. x hope this helps....
