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y = 3√x

y = 3x^(1/2)

y' = 3(1/2)x^(1/2 -1)

y'= (3/2)x^(-1/2)

y' = 3/[2x^(1/2)]

y' = 3/(2√x)

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Q: Differentiate 3 Sq root x
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