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Q: Discriminant for 4x squared plus 4x plus 1?

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(2x-1)(2x-1) = 4x^2 -4x + 1

x = -½

OK. 4x2 + 4x + 1 = (2x + 1)2

4x(4x^2 + 3x + 1)

(4x - 1)(x - 5)

(4x - 3)(x - 1)

2(x - 1)(2x + y)

(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5

(4x + 1)(2x + 3)

4x2 + 1 + x2 + 3 = 5x2 + 4

There is no rational factorisation.

x2 + 4x + 3 =(x + 3) (x + 1)

(5x 2 - 8x + 1) + (2x 2 - 4x - 11)

X=1/2

(2x - 1)(6x + 5)

-1

It is 1/(4x)2

(2x - 1)(2x + 5)

The answer is (2x^2+3)(4x+1)

The discriminant is 1.

2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+

4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)

The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1

4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2

sqrt(4x+7) -4 = sqrt(4x-1) squared : (sqrt(4x+7) -4)2 = 4x-1 (4x+7) - 2x4xsqrt(4x+7) +16 = 4x-1 -8xsqrt(4x+7) = -24 sqrt(4x+7) = -24/-8 = 3 squared : 4x+7 = 32 = 9 4x = 9-7 = 2 then x=1/2