B squared -4ac is the discriminant. you get 0, which means it will have one rational solution.
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
2(x - 1)(2x + y)
4x2 + 1 + x2 + 3 = 5x2 + 4
X=1/2
(2x - 1)(6x + 5)
(2x-1)(2x-1) = 4x^2 -4x + 1
x = -½
Re=Write as 16x^(3) + 12x^(2) + 4x Take out the common factor of '4' Hence 4(4x^(3) + 3x^)2) + x) Take out the common factor of 'x' Hence 4x( 4x^(2) + 3x + 1) The answer!!!!!
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
2(x - 1)(2x + y)
4x2 + 1 + x2 + 3 = 5x2 + 4
x2 + 4x + 3 =(x + 3) (x + 1)
(4x + 1)(2x + 3)
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There is no rational factorisation.
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
X=1/2