B squared -4ac is the discriminant. you get 0, which means it will have one rational solution.
4x(4x^2 + 3x + 1)
2(x - 1)(2x + y)
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
4x2 + 1 + x2 + 3 = 5x2 + 4
X=1/2
(2x-1)(2x-1) = 4x^2 -4x + 1
x = -½
OK. 4x2 + 4x + 1 = (2x + 1)2
4x(4x^2 + 3x + 1)
(4x - 1)(x - 5)
(4x - 3)(x - 1)
2(x - 1)(2x + y)
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
4x2 + 1 + x2 + 3 = 5x2 + 4
(4x + 1)(2x + 3)
There is no rational factorisation.
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