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y8 divided by y3 = y5
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∙ 14y ago
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How do you do Y-8 divided by y plus 1 equals 1 over 3 solving for y?
(Y-8)/Y + 1 = 1/3 Multiply both sides by Y Y - 8 + Y = 1/3Y Combine like terms 2Y - 8 = 1/3Y Add 8 to both sides, subtract 1/3 Y from both sides (1 and 2/3)Y = 8 Divide by 1 and 2/3 Y = 4.8
-10 equals 8 plus 3y?
Y=-3. -8 on both sides and divide by3 -10 = 8 + 3y -18 = 3y -6 = y or y = -6
What is the product of 7 and y to the third power when y 2?
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
What is the answer for these expressions y equals 3 parenthesis -3over2 parenthesis to the power of 2 plus 9 parenthesis -3over2 parenthesis -8?
If you mean: y = 3(-3/2)2+9(-3/2)-8 Then: y = -59/4 or as -14.75
What is 3y plus 5 equals y minus 3?
3y+5=y-3 subtract the y from the other side then: 2y+5=-3 subtract the 5 2y=-8 then divide 2 by both sides and your final answer should be: y= - 4
What is the result if you divide negative 12 x to the 8th power Y to the 8 power by 3 x to the 4th power Y to the 2nd power?
-12 x8 y8 / 3x4 y2 = -4 x4y6 First: divide -12 by 3 which equals -4 Second: divide x to the power of 8 by x to the power of 4 by subtracting the two powers ( 8-4 ) which will equal x to the power of 4 Third: divide y to the power of 8 by y to the power of 2 by subtracting the two powers ( 8-2 ) which will equal y to the power of 6
What is y to the 6th power divided by y to the 5th power?
1.2
How many eighth's are in one third?
To find out how many of x are in y, divide y by x.To find how many 1/8 are in 1/3, divide 1/3 by 1/8:(1/3) / (1/8) = (1/3) x (8/1) = 8/3 = 2 2/3
How do you do Y-8 divided by y plus 1 equals 1 over 3 solving for y?
(Y-8)/Y + 1 = 1/3 Multiply both sides by Y Y - 8 + Y = 1/3Y Combine like terms 2Y - 8 = 1/3Y Add 8 to both sides, subtract 1/3 Y from both sides (1 and 2/3)Y = 8 Divide by 1 and 2/3 Y = 4.8
-10 equals 8 plus 3y?
Y=-3. -8 on both sides and divide by3 -10 = 8 + 3y -18 = 3y -6 = y or y = -6
What is the product of 7 and y to the third power when y 2?
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
How do you factor Y to the 8th power -81?
89
What is y to the 5th power times y to the 3rd power times y?
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
25y to the power of 8 divided by 15y to the power of 5?
25y**8/15y**5 25y**3/15 5y**3/3 (5/3)y**3
Solve 2 bracket y plus 3 equals 22?
=> 2(y+3) = 22{divide both sides by 2}=> y+3 = 22/2 = 11{subtract 3 from both sides}=> y = 11-3 = 8y = 8
The only integer n for which n equals x to the y power equals y to the x power for x is not equal to y?
This is definitely false; if x=2 and y=3, x to the y power is 8, but y to the x power is 9, which are not equal.
Gfc for y to 6 power y to 7 power y to 8 power?
y^6
