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Coefficient of the fourth term of the expansion of x-y to the 6th power?
fourth term of X-Y to the sixth power
What is the image of P for a dilation with center (0 0) and a scale factor of 2.5?
It is (2.5x, 2.5y) where P =(x,y).
What is the image of P for a dilation with center 0 0 and a scale factor of 2.5?
It is (2.5x, 2.5y) where P =(x,y).
Are the answers to area of triangle squared?
It is 1/4*base2*(vertical height)2 in units of length to the fourth power. If the lengths of the sides are X, Y and Z, then the area squared is (X + Y + Z)*(- X + Y + Z)*(X - Y + Z)*(X + Y - Z)/16
What is equivalent to 7x-14?
21
What is the greatest common factor of y to 8th power y to 6th power and y to 4th power?
y4
How do you factor 9x2-6xy y2-81?
(3x - y)(3x - y) - 81
Factor 9x squared - 6xy plus y squared - 81?
Type your answer here... 81
What is the square root of y to the second power over 81?
(y2/81)1/2 = y/9
Factor 9x squared minus 6xy plus y squared minus 81?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
How do you factor y2-81?
There is a formula for the "difference of squares." In this case, the answer is (y + 9)(y - 9)
How do you factor 9xx-6xy yy-81?
(3x - y + 9)(3x - y - 9)
How would you factor 9x2 - 6xy plus y2 - 81?
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
How do you factor this Y3 plus 2y2 - 81y - 162?
y3 + 2y2 - 81y -162 = y2(y+2) - 81(y+2) =(y+2)(y2-81) = (y+2)(y-9)(y+9)
Is y minus 3 a factor of y to the fourth power plus 2 y to the second power minus 4?
No.
How do you factor 9x2-6xy plus y2-81?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 (since the first three terms make a perfect square = (3x - y - 9)(3x - y + 9) since the expression now is a difference of two squares.
How do you completely factor x to the fourth power minus y to the fourth power?
It is: (x-y)4
