No, the set of Irrational Numbers has a cardinality that is greater than that for rational numbers. In other words, the number of irrational numbers is of a greater order of infinity than rational numbers.
Yes, there are.
Yes, fewer by an order of infinity.
Yes, there are countably infinite rationals but uncountably infinite irrationals.
Yes. If its irrational it just means that it continues forever with no real pattern. It can still have real numbers
For any given subset, yes, because there are an infinite number of irrational numbers for each rational number. But for the set of ALL real numbers, both are infinite in number, even though the vast majority of real numbers would be irrational.
The main subsets are as follows:Real numbers (R) can be divided into Rational numbers (Q) and Irrational numbers (no symbol).Irrational numbers can be divided into Transcendental numbers and Algebraic numbers.Rational numbers contain the set of Integers (Z)Integers contain the set of Natural numbers (N).
Yes. The infinity of rational numbers has the same size as the natural numbers, said to be "countable". The infinity of real numbers (and therefore, also of irrational numbers) is a larger infinity, said to be "uncountable".
They are irrational numbers!
They are numbers that are infinite
A surd is a number expressed as a square root (or some other root). Such roots are usually irrational; but irrational numbers also include other numbers, which CAN'T be expressed as the root of a rational number. For example, pi and e.
Irrational numbers are real numbers.