It's generally accepted that numbers range from 0 to 9. This is the fundamental basis of the decimal counting system. The first set of digits in a number represent the units. After the number 9 we move across into a second column where the digits in that column represent the tens. So we have a number such as 37 which means 3 x 10 plus 7 x 1. And so it continues with further columns representing hundreds, thousands etc.
Primera Coyote Starrk (1st Espada in Aizen's Arrancar Army) .
Numbers from 0 to 100 that are multiples of 10 are: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. That's ten numbers, so the fraction of numbers from 1 to 100 that are multiples of 10 is 10/100. In simplest form it is 1/10.
00101 converting numbers to binary code is simple and fun. write the number you want to know and divide the number by 2 dropping the remainder if there is one ex. 21 becomes 10 because 21 divided by 2 is 10 remainder 1. divide by two until the answer is '1'. now after each even number write a '0' and after each odd number write a '1'. starting from the top read the ones and zeros downward. here's 20 and then 144 20 0 10 0 5 1 2 0 1 1 read down "00101" 144 0 72 0 36 0 18 0 9 1 4 0 2 0 1 1 read down "00001001"
natural numbers are positive not including 0, so therefore, 10. 1 thru 10
To add the binary numbers 11011 and 1101, we start by aligning the numbers vertically and then adding each column from right to left. 1 + 1 = 10 in binary (0, carry 1), 1 + 0 = 1, 0 + 1 = 1, 1 + 1 = 10 (0, carry 1), and finally 1 + 1 = 10 (0, carry 1). Therefore, the sum of 11011 and 1101 in binary is 101000.
I'm guessing you mean, "What is 10 to the 0th power?"The answer, of course, is the same for 10, as it is for anything else, 1, because numbers greater than 1 to a negative power are less than 1, but greater than 0, and numbers greater than 1 to powers between 0 and 1 are between 1 and that number.
It is called the binary system. It uses only 2 numbers. The numbers are "0" and "1" This is a computer language. Base 10 is our regular number system... consisting of 10 numbers from 1-9 including 0
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
To add the binary numbers 10011 and 11011, align them like regular numbers and add from right to left. Starting from the right, the sum is: 1 + 1 = 10 (write down 0 and carry 1), 1 + 1 + 1 (carry) = 11 (write down 1 and carry 1), 0 + 0 + 1 (carry) = 1, 0 + 1 = 1, and finally 1 + 1 = 10 (write down 0 and carry 1). The final result is 101110 in binary.
A long string on numbers (integers).A long string on numbers (integers).A long string on numbers (integers).A long string on numbers (integers).
All numbers are read in order of most significant digit to least significant digit. Binary digits are read right to left the same way numbers increase from right to left (our system of base 10). Numbers do not increase the same way we read (left to right). This is the same way we add, multiply and subtract in math. We start from the numbers on the right and move left if you prefer to think of it that way. With our usual system of base 10 numbers, each digit starts from "ones", then "tens", "hundreds" and so on moving from right to left. The same is with binary except that binary is only base 2. A 1 in the first position = 2^0 = 1. A 1 in the second position = 2^1 = 2 where each "one" is added for the final value. See below for examples. Our base 10 system goes one more step by mulitplying each number as you go, expanding on the zeros and ones to zeros through nines: 5062 = 2*(10^0)+6*(10^1)+0*(10^2)+5*(10^3) = 5062 For a binary example, if there are 8 bits in a byte, we get the following possibilities: 00000000 = 0 00000001 = (2^0) = 1 00000010 = (2^1) = 2 00000011 = (2^0)+(2^1) = 3 and so on and so forth... 10101011 = (2^0)+(2^1) +(2^3)+(2^5)+(2^7) = 1+2+8+32+126 = 171 and finally 11111111 = the sum of 2^n where n stands for the numbers 0 -> 7 = (2^0)+(2^1) +(2^3)+(2^4)+(2^5)+(2^6)+(2^7)+(2^8) = 255
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }