There are 9 digits that can be the first digit (1-9);
for each of these there is 1 digit that can be the second digit (6);
for each of these there are 10 digits that can be the third digit (0-9);
for each of these there are 10 digits that can be the fourth digit (0-9).
→ number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
1000... 0600-0699 1600-1699 and so on.
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
The second digit can be 2,4,6, or 8. There are 4 ways of choosing the second digit. The first digit can be chosen from the remaining 8 digits. 8x4 = 32 numbers. Here, it is assumed that the numbers do not repeat
24
17
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
1000... 0600-0699 1600-1699 and so on.
4
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
The second digit can be 2,4,6, or 8. There are 4 ways of choosing the second digit. The first digit can be chosen from the remaining 8 digits. 8x4 = 32 numbers. Here, it is assumed that the numbers do not repeat
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
24
17
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
There are 2941 4-digit numbers such no two of its digits differ by 1.
3 digit numbers are lessthan 4 digit numbers
If this is a homework assignment, please consider trying it yourself first, otherwise the value of the reinforcement to the lesson offered by the homework will be lost on you.There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9. (5 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit - multiply 5, 4, and 3, and you get 60.)To determine how many of these three digit numbers are smaller than 500, consider that, given 2 4 6 8 and 9, the first digit would have to be 2 or 4. That gives 2 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit. Multiply 2, 4, and 3, and you get 24.