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Yes you do, you also flip the inequality sign if you multiply by a negative #

The > and < signs are strictly the "Greater than" and "Less than" signs. The inequality sign is an = with a / stroke through it. If you divide an inequality by -1 it remains an inequality.

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12y ago

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If you multiply or divide both sides of an inequality by a number you need to reverse the inequality sign?

negative flip


When you divide both sides of any inequality by a negative number you need to what the inequality symbol?

Flip it around


When is the only time you flip an inequality sign?

When you divide both sides of an inequality by a negative number, the inequality sign flips.


Do you flip the sign of this inequality 8x plus 4y12?

Only when you multiply or divide by a negative number


Do you flip the inequality sign if the only the variable is negative?

No, you only flip the inequality sign if you are dividing by a negative number on both sides of the inequality


Do you flip the inequality when adding and subtracting?

No. Only flip the inequality when multiplying or dividing by a negative number.


When do you have to flip the greater than or less than or equal to sign in a inequality equation?

You need to flip the inequality sign when you multiply or divide both sides of the inequality by a negative number. For example, if you have an inequality like ( -2x &lt; 6 ) and you divide by -2, it becomes ( x &gt; -3 ). However, when adding or subtracting a number from both sides, the inequality sign remains unchanged.


When you divide both sides of an inequality by a negative number you need to blank the inequality symbol?

Flip. You need to reverse the inequality when multiplying or dividing by a negative. -2x &lt; 10 (-1)*(-2x) &lt; (-1)*10 2x &gt; -10 x &gt; -5


Why must you flip the inequality symbol when you divide by a negative number?

For the same reason you must flip it when you multiply by a negative number. An example should suffice. 2 &lt; 3 If you multiply by -1, without switching the sign, you get: -2 &lt; -3, which is wrong. Actually, -2 &gt; -3. Look at a number line if you are not sure about this - numbers to the left are less than numbers further to the right. Dividing by a negative number is the same as multiplying by the reciprocal, which in this case is also negative. These signs are strictly the "Greater than" and "Less than" signs. The inequality sign is an = with a / stroke through it. If you divide an inequality by -1 it remains an inequality.


What must you do when solving an inequality with a negative coefficient?

Divide by negative one and flip the sign eg -x &gt; 6 / -1 /-1 x &lt; - 6


How do you solve an inequality with a negative coefficient?

The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)


Does an inequality change when you multiply by a negative?

Yes you have to flip the sign.