The easiest way is to "flip" the inequality symbol end divide by the negative number:
Example:
6 < 3 - 3s
6 - 3 < 3 - 3s -3
3 < -3s Method a) Divide by negative coefficient and flip the inequality symbol
3/-3 > -3s/-3
-1 > s or s< -1
3 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides
3 +3s < -3s + 3s
3 + 3s < 0
3 - 3 + 3s < 0 -3
3s < -3
3s/3 < -3/3
s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
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If you're multiplying or dividing by a negative number there is one rule you should do which is flip a sign.
Divide by negative one and flip the sign eg -x > 6 / -1 /-1 x < - 6
Yes, a coefficient of a variable can be negative.
9h + 2 < - 79 9h < - 81 h < - 9
x>-9
Always.