ewan
4x + 32 = 4(x + 8)
An expression is a statement of terms and has no equal sign. An equation is a statement of two terms that equal each other.
It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares
Completely Factored
You don't. That expression can not be factored. You can see that by observing that the only factors of the last term, 1 and 5, can not be added or subtracted from each other in any way that gives a sum of 10 (the coefficient of the middle term).
I think it's: n2+5
So, you like, think of an explanation for why they may or may not be related to each other, and then you like, uh.... Explain to someone else why they happen to be similiarate
The expression (3x^3 + 5y^3 + 14) is already in its simplest form, as it consists of distinct terms that cannot be combined or factored further. Each term has different variables and powers, preventing any simplification through addition or factoring. Therefore, there are no common factors or like terms to simplify in this expression.
The expression ( x^6 - 64y^6 ) can be recognized as a difference of squares, which can be factored as ( (x^3 - 8y^3)(x^3 + 8y^3) ). Each of these terms can be further factored using the sum and difference of cubes formulas. Thus, the complete factorization is ( (x - 2y)(x^2 + 2xy + 4y^2)(x + 2y)(x^2 - 2xy + 4y^2) ).
What are the types of backup Explain each?
Replace each variable in the expression by its value and then find the value of the expression.
k^(2) - 9h^(2) First recognise that '9' = 3^(2) Hence k^(2) - 3^(2)h^(2) => k^(2) - (3h)^(2) (Factor (k - 3h)( k + 3h) Fully factored. NB First if any coefficients are squared numbers. Secondly, two squared terms with a negative(-) between them factors. This does NOT happen if there is a positive(+) between. Lastly the bracketed terms should each have a different sign. NNB The Pythagorean Eq'n ; h^(2) = a^(2) + b^(2) does NOT factor. However, if algebraically rearranged to ; a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b)