(x - 5)(x - 5)
the only thing you can do to this is factor it... (x + 5)(x + 5) x=-5
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
(x - 5)(x - 5)
(x+5)^2 and therefore x = -5
(x - 5)(x - 5)
the only thing you can do to this is factor it... (x + 5)(x + 5) x=-5
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x2 + 10x + 25 --> (x + 5)2
(x - 5)(x - 5)
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
X3 + 10X2 + 25Xfactor out an XX(X2 + 10X + 25)factor inside parenthesesX(X + 5)(X + 5)X(X + 5)2=======X = 0X = - 5
(x+5)^2 and therefore x = -5
Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33
5
-2-5