Yes. It goes in 141 times.
Well, honey, 4 goes into 564 a grand total of 141 times. So, if you're looking to divide that bad boy up, you've got yourself 141 little chunks of 4 in that 564. Hope that helps, darling!
80 with remainder 4.
141
564 over 141 in lowest terms = 4/1 = 4
They are 1, 2, 3, 4, 6, 12, 47, 94, 141, 188, 282, and 564.
70.5
564 rounded to the nearest tens place is 560
(1, 564) (2, 282) (3, 188) (4, 141) (6, 94) (12, 47)
1, 2, 3, 4, 6, 12, 47, 94, 141, 188, 282, 564.
By "Why" I guess you mean "what test can be used to find the divisibility" as opposed to "showing what multiple works".Test of divisibility by4If last 2 digits divisible by 4, the whole number is divisible by 4. 564 → 64 which is divisible by 4 (64 = 4 x 16), so 564 is divisible by 4(564 = 4 x 141)66 = 2 x 3, so the number must pass both the divisibility tests for 2 & 3: 2The number is even (the last digit is divisible by 2) 564 → 4 which is even (4 = 2 x 2), so 564 is divisible by 2(564 = 2 x 282)3Add the digits together and if the resulting number is divisible by 3, so is the original number. 564 → 5 + 6 + 4 = 15 which is divisible by 3 (15 = 3 x 5), so 564 is divisible by 3(564 = 3 x 188)564 passes both tests, so it is divisible by 6 (564 = 6 x 94)9Add the digits together and if the resulting number is divisible by 9, so is the original number 564 → 5 + 6 + 4 = 15 which is not divisible by 9, so 564 is not divisible by 9Thus 564 is divisible by 4 and 6, but not by 9.In the tests for 3 and 9, if the result of the addition is more than 1 digit, the test can be reapplied to the result of the addition, so if the digits of sum are added together until a single digit remains, thenif the digit is 3, 6 or 9, it is divisible by 3 and so the original number is divisible by 3if it is 9, then the original number is also divisible by 9.
4,564,000
564