1 x 6 = 6 6 x 9 = 54 54 - 4 = 50 So: 1 x 6 x 9 - 4 = 50
3/4 x 9 = 27/4 or 6 and 1/4
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6, 9 x 4, 12 x 3, 18 x 2, 36 x 1
Assuming you need to do a 'sum' to find each number... 1 x 1 = 1 1 x 2 = 2 4 - 1 = 3 4 x 1 = 4 4 + 1 = 5 4 + 2 = 6 9 - 2 = 7 4 x 2 = 8 9 x 1 = 9 and 9 + 1 = 10 !
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6, 9 x 4, 12 x 3, 18 x 2, 36 x 1
1 x 6 = 6 6 x 9 = 54 54 - 4 = 50 So: 1 x 6 x 9 - 4 = 50
4 x 9, 6 x 6 , 12 x 3, 36 x 1 all make 36.
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6.
1, 2, 3, 4, 6, 9, 12, 18, 36:1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6
1 x 36 2 x 18 3 x 12 4 x 9 6 x 6 9 divisors (1, 2, 3, 4, 6, 9, 12, 18, 36)
(2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 will have a remainder of 1 when divided by 2, 3, 4, 5, 6, 7, 8, or 9. (2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 = 362,881
9(6 + x) = 1
Aside from zero (0x0 = 0), the first 6 squares of integers are 1, 4, 9, 16, 25, and 36. 1 x 1 = 1 2 x 2 = 4 3 x 3 = 9 4 x 4 = 16 5 x 5 = 25 6 x 6 = 36
Assuming you have to use all of the numbers: (9 - 4 - 1) x 6 = 24
3/4 x 9 = 27/4 or 6 and 1/4
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6, 9 x 4, 12 x 3, 18 x 2, 36 x 1
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6, 9 x 4, 12 x 3, 18 x 2, 36 x 1