A square with 4 right angles and has a point of a triangle on the end of the square
The 2 diagonals of a rhombus intersect at right angles
That's three different shapes: a rectangle, a rhombus and a trapezoid respectively.
Yes, (with 1 exception) all rhombi will have 2 congruent acute angles, and 2 congruent obtuse angles. The 1 exception is if the rhombus is a square, then all angles will be right angles.
there are no right angles in a rhombos, but there are 2 obtuse angles and 2 acute angles.
yes, except for the special case rhombus which is a square. A square has 4 right angles.
rhombus if only 2 sides are parallel but 2 others are not, then it is a trapezoid (trapezium)
facts about rhombus's: 1) a rhombus is a parallelogram with all four sides of equal length. 2) the sum of the angles inside a 4-sided polygon is 360 degrees. 3) in a rhombus the two opposing corners must be the same angle in order for (1) to be true. therefore: the only way to draw a rhombus with 2 right angles, is to actually draw one with 4 right angles a.k.a. a square
a rhombus
One difference is that a square has right angles, but a rhombus only has acute and obtuse angles. A similarity is that if you tilt a square it turns into a rhombus. Another similarity is that they are both Quadrangles. Another difference is that Rhombus lines are slanted. Hoped that helped! ;0)
rhombus
it has 4 equal sides and no right angles